更多"有如下程序: #include <iostream> using "的相关试题:
[填空题]有如下程序:
#include <iostream>
using namespace std;
int strle(char a[],char b[])
{
int num=O,n=O;
while (* (a+num) !=’/0’)
num++;
while (b [n] )
{
* (a+num)=b [n];
num++;
n++;
}
return(num);
}
int main ( )
{
char strl[80],str2[80],*p1=str1,*p2=str2;
cin>>p1;
cin>>p2;
cout<<strle(p1,p2)<<end1;
return 0;
}
运行上述程序,如果从键盘输入字符串qwerty和字符串abcd,则程序的输出结果是 【7】 。
[单项选择]有如下程序
#include<iostream>
using namespace std;
class base
public:
virtual void f1( )
cout<<"F1Base";
virtual void f2( )
cout<<"F2Base";
;
class derive:public base
void f1( )
cout<<"F1 Derive";
void f2(int x)
cout<<"F2 Derive";
;
int main( )
base obj1,*p;
derive obj2;
p=& obj2;
p->f1( );
p->f2( );
return ( );
)
执行后的输出结果是( )。
A. F1Derive F2Base
B. F1Derive F2Derive
C. F1Base F2Base
D. F1Base F2Derive
[单项选择]有如下程序
#include <iostream>
using namespace std;
class basepublic:
virtual void f1( )
cout<<"F1Base ";
virtual void f2( )
cout<<"F2Base ";
;
class derive: public base void f1( )
cout<<"F1Derive ";
void f2( int x )
cout<<"F2Derive ";
;
int main( ) base obj1, * p;
derive obj2;
p = & obj2;
p -> f1( );
p -> f2( );
return 0; 执行后的输出结果是
A. F1Derive F2Base
B. F1Derive F2Derive
C. F1Base F2Base
D. F1Base F2Derive