题目详情
当前位置:首页 > 职业培训考试
题目详情:
发布时间:2024-02-18 23:51:19

[单选题]如图所示,为某电路的一部分,已知Uab=0,则I为
A.0A
B.1.6A
C.2A
D.4A

更多"[单选题]如图所示,为某电路的一部分,已知Uab=0,则I为"的相关试题:

[单选题]如图所示为某电路的一部分,图中哪两点间等效电阻最大
A.AB间
B.BC间
C.CD间
D.DA间
[单选题]如图所示为某电路的一部分,三个电阻的阻值均为R。若在AB间加上恒定电压,欲使AB间获得最大功率,应采取的措施是
A.S1、S2都断开
B.S1、S2都闭合
C.S1闭合、S2断开
D.S1断开、S2闭合
[单选题] 如图所示,已知UAB为10V,在R1上的电压降U1为5V,电流IAB为5A,求R2上的电压降U2和电阻R2值 符合下列选项的是()。
A.5V,1 Ω
B.5V,2 Ω
C.10V,1 Ω
[单选题]如图所示电路,a、b两点开路电压Uab为
A.5V
B.-5V
C.25V
D.15V
[单选题]如图所示电路中,a、b两点开路电压Uab为
A.6V
B.4V
C.14V
D.12V
[单选题]如图所示电路中,电流I和电压UAB的值分别为
A.I=2A、UAB=0
B.I=3A、UAB=-2V
C.I=-3A、UAB=10V
D.I=-3A、UAB=0
[单选题]
如图所示,若已知元件A吸收功率10W,则电流I为
()A。
A.1A
B.-5A
C.5A
D.6A
[单选题]在如图所示的网络中,三台交换机运行 RSTP 配置情况如图所示。根据图中配置情况,判断根交换机为
A.SWA
B.SWB
C.SWC
D.无法确定
[单选题]
已知一个已调幅信号的频谱如图所示,则已调信号的
带宽为()
A.2kHz()()

B.999kHz

C.1001kHz()()

D.1001kHz()()
[单选题]
设电路的电流参考方向如图所示,已知I<0,则电
流的实际方向为()。
A.电流由a至b

B.电流由b至a

C.都有可能

D.没有电流
[简答题]如图所示,已知A点高程为30.725m,计算B点高程及A、B两点高差。
[判断题]如图所示导体中的电流方向和小磁铁插入线圈时,线圈中产生的电流方向已知,图中标出的小磁铁N极和S极是正确的。(){Ja4E2060.png}
A.正确
B.错误
[简答题]如图所示的管道中,大管内径为100mm,逐渐缩小至80mm,已知甲烷在大管中的速度为10 m/s,甲烷的密度为1.4 kg/m3,在大小管的管壁上装有一个U型管压差计,指示液为水,若不计阻力损失,求读数R为多少?
[单选题]
如图所示,若已知通过元件的电流i(t)=30e−
=3.tA,t>0;且q(t)=0,t≤0,则电荷q(t)
的表达式应为()。
A.Style="font-size:20px;">Class="textarea">Data-cke-editable="1"
Contenteditable="false">Nmathquill-command-id="4">1Mathquill-command-id="5">0Class="错误n-leaf"
Mathquill-command-id="6">Style="transform:scale(1.08,1.47);"
Class="scaledparen">(Class="错误n-leaf"mathquill-block-id="7">Mathquill-command-id="8">1Class="binary-operator"
Mathquill-command-id="10">−Mathquill-command-id="17">eClass="错误n-leaf"mathquill-command-id="13"
Mathquill-block-id="14">Mathquill-command-id="18">−Mathquill-command-id="19">3Mathquill-command-id="20">t
Class="scaledparen">)Mathquill-command-id="21">CMathquill-command-id="22">,Mathquill-command-id="23">tClass="binary-operator"
Mathquill-command-id="24">>Mathquill-command-id="25">0>

B.Style="font-size:20px;">Class="textarea">Data-cke-editable="1"
Contenteditable="false">Nmathquill-command-id="146">5Class="错误n-leaf"
Mathquill-command-id="119">Style="transform:scale(1.08,1.47);"
Class="scaledparen">(Class="错误n-leaf"
Mathquill-block-id="121">Mathquill-command-id="120">1Class="binary-operator"
Mathquill-command-id="122">−Mathquill-command-id="124">eClass="错误n-leaf"mathquill-command-id="126"
Mathquill-block-id="128">Mathquill-command-id="127">−Mathquill-command-id="129">3Mathquill-command-id="131">t>Class="scaledparen">)Mathquill-command-id="136">ℂMathquill-command-id="138">,Mathquill-command-id="140">tClass="binary-operator"
Mathquill-command-id="142">>Mathquill-command-id="144">0N>

C.Style="font-size:20px;">Class="textarea">Data-cke-editable="1"
Contenteditable="false">Nmathquill-command-id="4">1Mathquill-command-id="6">0Class="错误n-leaf"
Mathquill-command-id="9">Style="transform:scale(1.08,1.47);"
Class="scaledparen">(Class="错误n-leaf"mathquill-block-id="11">Mathquill-command-id="10">1Class="binary-operator"
Mathquill-command-id="12">−Mathquill-command-id="14">eClass="错误n-leaf"mathquill-command-id="16"
Mathquill-block-id="18">Mathquill-command-id="17">−Mathquill-command-id="36">6Mathquill-command-id="21">t
Class="scaledparen">)Mathquill-command-id="26">ℂMathquill-command-id="28">,Mathquill-command-id="30">tClass="binary-operator"
Mathquill-command-id="32">>Mathquill-command-id="34">0>

D.Style="font-size:20px;">Class="textarea">Data-cke-editable="1"
Contenteditable="false">Nmathquill-command-id="36">5Class="错误n-leaf"
Mathquill-command-id="9">Style="transform:scale(1.08,1.47);"
Class="scaledparen">(Class="错误n-leaf"mathquill-block-id="11">Mathquill-command-id="10">1Class="binary-operator"
Mathquill-command-id="12">−Mathquill-command-id="14">eClass="错误n-leaf"mathquill-command-id="16"
Mathquill-block-id="18">Mathquill-command-id="17">−Mathquill-command-id="37">6Mathquill-command-id="21">t
Class="scaledparen">)Mathquill-command-id="26">ℂMathquill-command-id="28">,Mathquill-command-id="30">tClass="binary-operator"
Mathquill-command-id="32">>Mathquill-command-id="34">0>
[简答题]如图所示,K型热偶误用了分度号为E的补偿导线,但极性连接准确,则仪表指示如何变化?已知t=500℃,t1=30℃,t0=20℃,Ek(500℃,20℃)=20.640mV,Ek30℃,0℃)=10203mV,EE(30℃,0℃)=1.801mV,EE(20℃,0℃)=1.192mV,Ek(20℃,0℃)=0.798mV。
[简答题]如图所示,用法兰液面计测量闭口容器的界位,已知h1=20cm,h2=20cm,h3=200cm,h4=30cm,被测轻液体密度ρ1=0.8g/cm³,重液体密度ρ2=1.1g/cm³,液面及毛细管内的硅油密度ρ0=0.95g/cm³,求 1)仪表的量程和迁移量? 2)仪表在使用过程中改变位置,对输出有无影响?
[简答题]3.59.
如图所示,已知I=20mA,I2=12mA,R1=2kΩ,R2=3kΩ,R3=9kΩ。求表A1的读数______mA和A2的读数______mA。
[单选题]如图所示,表示意义是什么
A.收到ZC/ATS发送的列车故障信息
B.收到ZC/ATS发送的停稳信息
C.收到屏蔽门故障信息
D.收到车门故障信息

我来回答:

购买搜题卡查看答案
[会员特权] 开通VIP, 查看 全部题目答案
[会员特权] 享免全部广告特权
推荐91天
¥36.8
¥80元
31天
¥20.8
¥40元
365天
¥88.8
¥188元
请选择支付方式
  • 微信支付
  • 支付宝支付
点击支付即表示同意并接受了《购买须知》
立即支付 系统将自动为您注册账号
请使用微信扫码支付

订单号:

请不要关闭本页面,支付完成后请点击【支付完成】按钮
恭喜您,购买搜题卡成功
重要提示:请拍照或截图保存账号密码!
我要搜题网官网:https://www.woyaosouti.com
我已记住账号密码