更多"能将程序补充完整的选项是 class Person { pr"的相关试题:
[单项选择]能将程序补充完整的选项是
class Person
private int a;
public int change(int m)return m;
public class Teacher extends Person
public int b;
public static void main(String arg[])
Person p=new Person( );
Teacher t=new Teacher( );
int i;
____
A. i=m
B. i=b
C. i=p.a
D. i=p.change(50)
[单项选择]能将程序补充完整的选项是( )。
class Person
private int a;
public int change(int m)return m;
public class Teacher extends Person
public int b;
public static void main(String arg[])
Person P=new Person( );
Teacher t=new Teacher( );
int i;
________
A. i=m
B. i=b
C. i=P.a
D. i=P.change(50)
[单项选择]能将程序补充完整的选项是______。
class Person
private int a;
phblic int change(int m)return m;
public class Teacher extends Person
public int b;
public static void main(String arg[ ])
Person p=new Person( );
Teacher t=new Teacher( );
int i;
______;
A. i=m
B. i=b
C. i=p.a
D. i=p.change(50)
[单项选择]在下列程序的划线处应填入的语句是( )。 class Person private int a: public class Man extends Person public int b; public static void main(String arg []) Person p=newPerson( ); Man t=new Man( ); int i; _________________
A. i=w;
B. i=b;
C. i=P.a;
D. i=t.b;
[单项选择]在下列程序的划线处应填入的语句是
class Person
private int a;public class Man extends Person
public int b;
public static void main (String arg [])
Person p=new Person( );
Man t=new Man( );
int i:
A. i=w;
B. i=b
C. i=p.a;
D. i=t.b;
[单项选择]能将程序补充完整的选项是( )。 classPerson { privateinta; publicintchange(intm){returnm;} } publicclassTeacherextendsPerson { publicintb; publicstaticvoidmain(Stringarg[D { Personp=newPerson( ); Teachert=newTeacher( ); inti; } }
A. i=m
B. i=b
C. i=a
D. i=change(50)
[填空题]下面是一个类的定义,试将程序补充完整。
class A
String s;
____int a=66;
A(String sl)
s=sl;
static int geta( )
return a;
[填空题]根据程序中的注释将下列缺失部分补充完整。
class Point{
int x, y; //点的x和y坐标
public:
Point(int xx=0,int yy=。):x(xx),y(yy){}
};
class Circle{
Point center;//圆心位置
int radius; //半径
public: //利用cx和cy分别初始化圆心的x和y坐标
Circle(int cx;int cy,int r):__【12】__,radius(r){}
void area(){cout<<3.14159*radius*radius<
[填空题]将下面程序补充完整。
public class PowerCale
public static void main(String[] args)
double x=5.0;
System.out.println(x+"to the power 4 is"+power(x,4));
System.out.println("7.5 to the power 5 is"+power(7.5,5));
System.out.println("7.5 to the power 0 is"+power(7.5,0));
System.out.println("10 to the power -2 is"+power(10,-2));
static double ______ (double x,int n)
if(n>1)return x * power(x,n-1);
else if(n<0)return 1.0/power(x,-n);
else return n==0 1.0:x:
[填空题]下列是一个类的定义,将程序段补充完整。
class A{
String s;
【10】 int a=66;
A (String s1) {s=s1; }
static int geta ( ) { return a: )
}
[填空题]将下面程序补充完整。
public class PowerCale {
public static void main(String[] args) {
double x=5.0;
System.out.println(x+"to the power 4 is"+power(x,4));
System.out.println("7.5 to the power 5 is"+power(7.5,5));
System.out.println("7.5 to the power 0 is"+power(7.5,0));
System.out.println("10 to the power -2 is"+power(10,-2));
}
static double ______ (double x,int n) {
if(n>1)return x * power(x,n-1);
else if(n<0)return 1.0/power(x,-n);
else return n==0 1.0:x:
}
}
[填空题]下列是一个类的定义,将程序段补充完整。
class A
String s;
【10】 int a=66;
A (String s1) s=s1;
static int geta ( ) return a: )